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What is the mass of 0.89 mol of CaCl₂?

Sagot :

Tessiemjcastleidn

Answer:

The mass of the given mole of CaCl_2CaCl

2

is required.

The mass of the given compound is 98.78 g.

Molar mass of CaCl_2CaCl

2

M=40.078+35.453\times 2=110.984\ \text{g/mol}M=40.078+35.453×2=110.984 g/mol

n = Number of moles = 0.89 mol

Mass is given by

\begin{gathered}m=Mn\\\Rightarrow m=110.984\times 0.89\\\Rightarrow m=98.78\ \text{g}\end{gathered}

m=Mn

⇒m=110.984×0.89

⇒m=98.78 g

The mass of the given compound is 98.78 g.