PrincessGiorgie9idn
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Sagot :

TheBlueStaridn

Part 1 :-

[tex] \\ [/tex]

Given :-

  • Distance = 120 km
  • T = 3 hrs.

[tex] \\ [/tex]

To find :-

  • Speed

[tex] \\ [/tex]

We know:-

[tex] \boxed{ \rm speed = \frac{distance}{time} }[/tex]

[tex] \\ [/tex]

So:-

[tex] \dashrightarrow \sf speed = \dfrac{distance}{time} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf speed = \dfrac{120}{3} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf speed = \cancel\dfrac{120}{3} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \bold{ speed = 40 \: kmh {}^{ - 1} }[/tex]

[tex] \\ \\ [/tex]

Part 2 :-

[tex] \\ [/tex]

Given :-

  • Distance = 400 km
  • Speed = 80 km/h

[tex] \\ [/tex]

To find :-

  • time

[tex] \\ [/tex]

we know:-

[tex] \boxed{ \rm time= \frac{distance}{speed} }[/tex]

[tex] \\ [/tex]

So:-

[tex] \dashrightarrow\sf time= \dfrac{distance}{speed} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\sf time= \dfrac{400}{80} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\sf time= \dfrac{40 \cancel0}{8 \cancel0} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\sf time= \dfrac{40}{8 } [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\sf time=\cancel \dfrac{40}{8 } [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow\bold{ time=5 \: hrs}[/tex]

1.

S = D ÷ T

S = 120km ÷ 3h

S = 40 km/h

The average speed is 40 km/h.

2.

T = D ÷ S

T = 400km ÷ 80 km/h

T = 5hrs

The time taken by the car to complete the journey of 400 km with average speed of km/h is 5 hrs.

Hope it helps!

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