f(n) = {1, 2, 3, 4, 5, 6 …}
Given: f(n) =
[tex] \binom{ \frac{n}{2} \: if \: in \: is \: even }{3n \: + 1 \: if \: n \: is \: add} [/tex]
To find: value
Solution:
[tex]f(n) = \binom{ \frac{n}{2}if \: is \: even }{3n + 1 \: if \: n \: is \: add} [/tex]
[tex]f(2) = \frac{2}{2} = 1[/tex]
[tex]f(4) = \frac{4}{2} = 2[/tex]
[tex]f(6) = \frac{6}{2} = 3[/tex]
[tex]f(1) = 3 + 1 = 4[/tex]
[tex]f(3) = 3 \times 3 + 1 = 10[/tex]
[tex]f(5) = 15 + 1 = 16[/tex]
