Magtanong at makakuha ng eksaktong mga sagot sa IDNStudy.com. Hanapin ang impormasyon na kailangan mo nang mabilis at madali sa pamamagitan ng aming komprehensibo at eksaktong platform ng tanong at sagot.
Answer:
\frac{4}{3}\pi R^3 \rho_s g = \frac{4}{3}\pi R^3 \rho g + \frac{1}{2} C_d \rho \pi R^2 w_s^2
\frac{4}{3}\pi R^3 \rho_s g = deposition of non-cohesive sediments
\pi = approx 3.14
R = radius of the spherical object being deposited
\rho = density of spherical object
g = gravitational acceleration
C_d = drag coefficient
w_s = particle's settling velocity