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Answered

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in how many ways can you choose the top 4 winners in a math Contest among 11 participants?​

Sagot :

Samuelrealon11idn

ANSWER

This is a basic counting principles, If there are k1 ways to do one task, and k2 ways to do another, then there are k1*k2 ways of doing both.

In this problem

k1 = 1O ways to choose first person to be chosen from the group of 10.

k2 = 9 ways for the second person to be chosen from the remaining people(10–1).

k3 = 8 ways for the second person to be chosen from the remaining people(9–1).

then all you need to do is multiply these k1 * k2 * k3.

Ans : 10 * 9 * 8 = 720

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