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Sagot :
To find the probability of drawing a particular card in each case :
• Total number of cards in the pack = 52
• Number of spades (black) = 13
Number of clubs (black) = 13
Number of hearts (red) = 13
Number of diamonds (red) = 13
• Probability of an event (P) = Number of favourable outcomes / Total number of possible outcomes
(i) • Probability of drawing a black king (P1) = Number of black kings / Total number of cards in the pack
• Number of black kings = King of spades + King of clubs
= 1 + 1 = 2
• P1 = 2 / 52 = 1 / 26
(ii) • Probability of drawing either a black card or a king (P2) = (Number of black cards + Number of kings in red cards) / Total number of cards
=> P2 = (26 + 2) / 52
Or, P2 = 28 / 52
Or, P2 = 7 / 13
(iii) Probability of drawing a card that is black and a king (P3) = Number of black kings in the pack / Total number of cards in the pack
=> P3 = 2 / 52
Or, P3 = 1 / 26
(iv) Probability of drawing a jack or a queen or a king (P4) = (Number of jacks + Number of queens + Number of kings) / Total number of cards
=> P4 = (4 + 4 + 4) / 52
Or, P4 = 12 / 52
Or, P4 = 3 / 13
(v) • Probability of drawing a heart or a king (Phk) = (Number of hearts + Number of kings in spades, clubs, and diamonds) / Total number of cards
=> Phk = (13 + 3)
Or, Phk = 16 / 52
Or, Phk = 4 / 13
• Now, probability of drawing neither a heart nor a king (P5) = 1 - Probability of drawing a heart or a king
=> P5 = 1 - (4 / 13)
=> P5 = (13 - 4) / 13
=> P5 = 9 / 13
(vi) Probability of drawing a spade or an ace (P6) = (Number of spades + Number of aces in hearts, clubs, amd diamonds) / Total number of cards
=> P6 = (13 + 3) / 52)
Or, P6 = 16 / 52
Or, P6 = 4 / 13
(vii) Probability of drawing neither an ace nor a king (P7) = 1 - Probability of drawing an ace or a king
• Now, probability of drawing an ace or a king (Pak) = (Number of aces + Number of kings) / Total number of cards
=> Pak = (4 + 4) / 52)
Or, Pak = 8 / 52
Or, Pak = 2 / 13
• Therefore, P(7) = 1 - (2 / 13)
=> P7 = (13 - 2) / 13
=> P7 = 11 / 13
(viii) Probability of drawing neither a red card nor a queen (P8) = 1 - Probability of drawing a red card or a queen
• Now, probability of drawing a red card or a queen (Prq) = (Number of red cards + Number of queens in black cards) / Total number of cards
=> Prq = (26 + 2) / 52
Or, Prq = 28 / 52
Or, Prq = 7 / 13
• P8 = 1 - Prq
Or, P8 = 1 - (7 / 13)
Or, P8 = (13 - 7) / 13
Or, P8 = 6 / 13
(ix) Probability of drawing an ace = 4 / 52 = 1 / 13
• Probability of drawing a card other than an ace (P9) = 1 - (1 / 13)
Or, P9 = (13 - 1) / 13
Or, P9 = 12 / 13
(x) Number of tens in the pack = 1 of spade + 1 of club + 1 of heart + 1 of diamond
= 4
Probability of drawing a ten = 4 / 52 = 1 / 13
(xi) Probability of drawing a spade (P11) = Number of spades / Total number of cards
=> P(11) = 13 / 52 = 1 / 4
(xii) Number of black cards = 26
Probability of drawing a black card (P12) = 26 / 52 = 1 / 2
(xiii) Probability of drawing the seven of clubs P(13) = Number of 7 in the club / Total number of clubs
=> P(13) = 1 / 13
(xiv) Probability of drawing a jack (P14) = Number of jacks / Total number of cards
=> P(14) = 4 / 52 = 1 / 13
(xv) Probability of drawing the ace of spades (P15) = Number of aces in the spade / Total number of spades
=> P(15) = 1 / 13
(xvi) Probability of drawing a queen (P16) = Number of queens in the pack / Total number of cards in the pack
=> P(16) = 4 / 52 = 1 / 13
(xvii) Probability of drawing a heart (P17) = Number of hearts in the pack / Total number of cards in the pack
=> P17 = 26 / 52 = 1 / 2
(xviii) Probability of drawing a red card (P18) = Number of red cards in the pack / Total number of cards in the pack
=> P18 = 26 / 52 = 1 / 2
(xix) Probability of drawing neither a king nor a queen (P19) = 1 - Probability of drawing a king or a queen
• Probability of drawing a king or a queen (Pkq) = (Number of kings + Number of queens in the pack) / Total number of cards in the pack
=> Pkq = (4 + 4) / 52
=> Pkq = 8 / 52
=> Pkq = 2 / 13
• Therefore, P19 = 1 - Pkq
=> P19 = 1 - (2 / 13)
Or, P19 = (13 - 2) / 13
Or, P19 = 11 / 13
correct me if I'm wrong and pa brainlies na den hehe thanks
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