Answered

IDNStudy.com, ang iyong mapagkukunan para sa malinaw at maaasahang mga sagot. Magtanong at makakuha ng detalyadong sagot mula sa aming komunidad ng mga eksperto.

@TheBlueStar
Help po pls

TheBlueStar Help Po Pls class=
TheBlueStar Help Po Pls class=
TheBlueStar Help Po Pls class=
TheBlueStar Help Po Pls class=
TheBlueStar Help Po Pls class=

Sagot :

TheBlueStaridn

It may not get messy that u even can't understand, therefore I will make some heading.

[tex] \\ [/tex]

Photo one:

[tex] \\ [/tex]

Part A.

[tex] \rm \angle ABD \cong \angle DBC[/tex]

This stament is completely False.

as :-

  • when ever we dive the angle of 90°, it isn't necessary they are equally divided.
  • it's clearly visible that angle ABD is larger than angle DBC.

[tex] \\ [/tex]

Part B.

[tex] \\ [/tex]

[tex] \rm \angle ABD \: is \: adjacent \: to \: \angle ABC[/tex]

This stament is completely False.

as:-

  • adjacent angles are those that have the same vertex and a side in common. where as here ABD is drived from angle ABC.

[tex] \\ [/tex]

Part C.

[tex] \\ [/tex]

[tex] \rm \angle ABD + \angle DBC = 90 {}^{ \circ} [/tex]

This stament is true.

as:-

  • whole angle ABC is 90°. we get to know due to boxed shape angle.

[tex] \\ [/tex]

Part D.

[tex] \\ [/tex]

[tex] \rm\angle DBC = \dfrac{ABC}{2} [/tex]

This statement is completely False.

as :-

  • Line BD does not go throughcorner of boxed angle.

[tex] \\ \\ [/tex]

Photo 2:-

[tex] \\ [/tex]

So this question is little tricky.

As here angle 1 = Angle 4 = Angle 5

Therefore Angle 3 is correct Answer

Salamat sa iyong kontribusyon. Huwag kalimutang bumalik at magtanong ng mga bagong bagay. Sama-sama tayong lumikha ng isang mas matibay na samahan. Sa IDNStudy.com, kami ay nangako na magbigay ng pinakamahusay na mga sagot. Salamat at sa muling pagkikita.