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Calculate the mass of Ba(OH)2 required to prepare 2.50 L of a 0.06 M solution of barium hydroxide.​

Sagot :

Dungcamariecrisidn

Answer:

g Ba(OH)2 = 2.50 L Ba(OH)2 * 0.2 mol Ba(OH)2 / 1 L Ba(OH)2 * 171.4 g Ba(OH)2 / 1 mol Ba(OH)2 g Ba(OH)2 = 85.7 g Ba(OH)2. Answer: 85.7 g Ba(OH)2 Explanation: M means molarity. Molarity means moles of solute per liters of solution. In our problem, molarity means moles of barium hydroxide per liters of barium hydroxide solution. We have 2.5 liters of 0.2 M barium hydroxide solution. Therefore, there is 0.2 moles of barium hydroxide per 1 liter of barium hydroxide solution. We have 2.5 liters of this solution; thus the number of moles of barium hydroxide we have is 2.5 * 0.2. Now...

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