[tex]\tt{\huge{\red{Solution:}}}[/tex]
Step 1: List the given values.
[tex]\begin{aligned} & \pi = \text{8.50 atm} \\ & T = 25^{\circ}\text{C} = \text{298.15 K} \end{aligned}[/tex]
Final Step: Calculate the molarity of the solution.
Note that 1 molar (M) is equal to 1 mole per liter (mol/L).
[tex]\begin{aligned} M & = \frac{\pi}{\text{RT}} \\ & = \frac{\text{8.50 atm}}{\left(0.082057 \: \dfrac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}}\right)(\text{298.15 K})} \\ & = \text{0.347 mol/L} \\ & = \boxed{0.347 \: M} \end{aligned}[/tex]
Hence, the molarity of the solution is 0.347 M.
[tex]\\[/tex]
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