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4.0 m/s
2.0 seconds
2.0 m/s.
UNKNOWN:
The acceleration of the boy.
a = average acceleration
v = final velocity
V_{0}V
0
= starting velocity
t = elapsed time
SOLUTION:
4.0m/s.+2.0 m/s.
=6.0 m/s^2
2. 6.25 m/s²
Given:
V = 25.0 m/s
t = 4.0 s
a=\frac{y}{t}a=
t
y
Substitute the values:
a=\frac{25.0 m/s} {4.0s}a=
4.0s
25.0m/s
a=6.25 m/s^{2}a=6.25m/s
2
3. FINAL VELOCITY
Given
Initial Velocity (u) = 90 km/h
Acceleration (a) = 5.0 m/s²
Time (t) = 2.0 s
Final Velocity (v) = ?
Convert from km/h to m/s
90 km/h / 3.6 = 25 m/s
v = u + at
v = 25 + (5.0)(2.0)
v + 25 + 10.0
v = 35.0 km/h