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1.
What is the Kinetic Energy
of a 1200 kg object that is moving with a speed of 24 m/s?
2. An object moving with a
speed of 67 m/s and has a kinetic energy of 500 J, what is the mass of the
object?
3. What is the Kinetic Energy
of a 478 kg object that is moving with a speed of 15 m/s?
4. An object moving with a
speed of 54 m/s and has a kinetic energy of 440 J, what is the mass of the
object.
Solve the following
word problems using the kinetic and potential energy formulas. (Write the given, formula, and show the step-by-step solution. Box the final answer with correct unit.)



1. Determine the kinetic energy of a 1000-kg
roller coaster car that is moving with a speed of 20.0 m/s.

2. Missy Diwater,
the former platform diver for the Ringling Brother's Circus had a kinetic
energy of


15,000 J just
prior to hitting the bucket of water. If Missy's mass is 50 kg, then what is
her speed?


3. A cart is
loaded with a brick and pulled at constant speed along an inclined plane to the
height of a seat-top. If the mass of the loaded cart is 3.0 kg and the height
of the seat top is 0.45 meters, then what is the potential energy of the loaded
cart at the height of the seat-top?


4.The potential
energy of a 40-kg cannon ball is 14000 J.
How high was the cannon ball to have this much potential energy?


5. An object has a kinetic
energy of 88 J and a mass of 45 kg , how fast is the object moving?


6. An object moving with a
speed of 55 m/s and has a kinetic energy of 180 J, what is the mass of the
object.


7. What is the mass of an object if its gravitational potential energy is 3822 J and it is
15m above the ground?

Sagot :

Boogsbagano12idn

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Donesjohnkennethidn

Answer:

1. To solve for the kinetic energy of a body we multiply one-half of it mass by the square of its speed.

K.E. = 1/2 * m * v^2

K.E. = 1/2 * 1200 kg * (24 m/s)^2

K.E. = 600 kg * 576 (m/s)^2

✅️K.E. = 345,600 joules

2. Note: 1 J = 1 kg•m²/s²

KE = ½mv²

KE = 500 J = 500 kg•m²/s²

v = 67 m/s

m = 2KE/v²

m = (2 × 500 kg•m²/s²)/(67 m/s)² = 0.22 kg

m = 0.22kg

3. KE = ½ mv2

KE = ?

m = 478kg

v = 15m/s

KE = ½ (478kg) (15 m/s)2

KE = ½ (478kg)(225)

KE = 53,775J

4. Repeat solution

II. Solve the following

word problems using the kinetic and potential energy formulas. (Write the given, formula, and show the step-by-step solution. Box the final answer with correct unit.)

1. The kinetic energy of the roller coaster is 2⋅10⁵ J

2. The kinetic energy formula is KE = ½mv².

Note: 1 J = 1 kg•m²/s²

Known and Unknown

KE = 15000 J = 15000 kg•m²/s²

m = 50 kg

v = ? m/s

Solve for v.

v² = 2KE/m

v² = (2 × 15000 m²/s²)/(50 kg) = 600 m²/s²

√(v²) = √(600 m²/s²)

v = 24.49 m/s = 20 m/s (rounded to one significant figure)

The speed is 20 m/s.

3. PE = m*g*h

PE = (3 kg ) * (9.8 m/s/s) * (0.45 m)

PE = 13.2 J

4. Given that

Mass of cannon ball m = 40 kg

Potential energy of cannon ball PE = 14000 joules

Acceleration due to gravity g = 10 m/s^2 g=10m/s²

Height of the cannon ball h = ?

Step 1: Calculation of the cannon ball height using the potential energy formula.

PE = mgh PE=mgh

14000 = 40 * 10 * h 14000=40∗10∗h

h = \frac{14000}{400} h=

400

14000

h = 35 h=35

Hence, cannon ball height

✅️ h=35 m

5. KE = ½ mv2

KE = 88J

m = 45kg

v = ?

2KE/m = v2 OR v2 = 2KE/m

v2 = 2(88J)/45kg

v2 = 3.91

v = 1.98m/s

6. Use the Kinetic Energy Formula. Para may idea po kayo makuha. Andun lang po sa mga answers yung formula.

7. Given that

Mass of object m = ?

Potential energy of an object, PE = 3822 joules

Height of the object h = 15 m

Acceleration due to gravity g = 9.8 m/s^2 g=9.8m/s²

Hence, mass of an object, m= 26kg

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