[tex]\tt{\huge{\red{Solution:}}}[/tex]
Note that there are 5 moles of C in 1 mole of NaC₅H₈NO₄ and there are 6.022 × 10²³ atoms of C in 1 mole of C.
[tex]\begin{aligned} \text{number of C atoms} & = 0.750 \: \cancel{\text{mol} \: \text{NaC}_5\text{H}_8\text{NO}_4} \times \frac{5 \: \cancel{\text{mol C}}}{1 \: \cancel{\text{mol} \: \text{NaC}_5\text{H}_8\text{NO}_4}} \times \frac{6.022 \times 10^{23} \: \text{C atoms}}{1 \: \cancel{\text{mol C}}} \\ & = \boxed{2.26 \times 10^{24} \: \text{C atoms}} \end{aligned}[/tex]
Hence, there are 2.26 × 10²⁴ C atoms in 0.750 mole of NaC₅H₈NO₄.
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