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1
If a jeepney travels at 100 km in 2 h, what is its average speed?
Given: Solution:
d=
t=
v=

Formula: v=d/t Final Answer:


2
John ran around the campus at a distance of 200 m in 2s. What was his average speed?
Given: Solution:
d=
t=
v=

Formula: v=d/t Final Answer:


Sagot :

VELOCITY

Problem #1:

» If a jeepney travels at 100 km in 2 h, what is its average speed?

Given:

  • d (distance) = 100 km
  • t (time) = 2 h
  • v (velocity) = ?

Formula:

  • [tex] \underline{ \boxed{ \tt v = \frac{d}{t} }}[/tex]

– To calculate the velocity, divide the given distance by the given time.

Solution:

- Substitute the given distance and time to the formula, we get...

  • [tex] \tt \: v = \frac{d}{t} \\ \: \: \: \: \: \: \: \: \: \: \tt \: v = \frac{100 \: km}{2 \: h} \\ \tt \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: v = \underline{ \boxed{ \blue{ \tt{50 \: km/h}}}}[/tex]

Final Answer:

  • [tex] \color{hotpink} \bold{50 \: km/h} \\ [/tex]

— — — — — — — — — —

Problem #2:

» John ran around the campus at a distance of 200 m in 2s. What was his average speed?

Given:

  • d (distance) = 200 m
  • t (time) = 2 s
  • v (velocity) = ?

Formula:

  • [tex] \underline{ \boxed{ \tt v = \frac{d}{t} }}[/tex]

– To calculate the velocity, divide the given distance by the given time.

Solution:

- Substitute the given distance and time to the formula, we get...

  • [tex] \tt \: v = \frac{d}{t} \\ \: \: \: \: \: \: \: \: \tt \: v = \frac{200 \: m}{2 \: s} \\ \tt \: \: \: \: \: \ \: \: \: \: \: \: \: \: \: v = \underline{ \boxed{ \blue{ \tt{100 \: m/s}}}}[/tex]

Final Answer:

  • [tex] \color{hotpink} \bold{100 \: m/s} \\ [/tex]

— — — — — — — — — —

Explanation:

– In problem #1, since the given distance is measured in kilometer (km) and given time is measured in hour (hr). Therefore, its velocity should be measured in km/hr.

– In problem #2, the given distance is measured in meters (m) and given time is measured in seconds (s). Therefore, its speed/velocity should be measured in meters per second (m/s).

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