IDNStudy.com, ang iyong platform ng sanggunian para sa pangkomunidad na mga sagot. Makakuha ng mga sagot sa iyong mga tanong mula sa aming mga eksperto, handang magbigay ng mabilis at tiyak na solusyon.

6 + 10 + 14 + ... + 38
Find the sum of the arithmetic series


Sagot :

[tex]\large{\tt{1:59\:pm\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:3/2/22}}[/tex]

[tex]\huge{\blue{\boxed{\gray{\mathbb{ANSWER}}}}}[/tex]

6 + 10 + 14 + ... + 38

Find the sum of the arithmetic series

  • [tex]\Large\sf{\underline{The\:sum\:of\:the\: series = \green{198}}}[/tex]

[tex]\\[/tex]

[tex]\huge{\red{\boxed{\gray{\mathbb{SOLUTION}}}}}[/tex]

» In the given arithmetic series:

  • The first term [tex]\rm{(a) = 6}[/tex]

  • Common difference [tex]\rm{(d) = (a_n - a_{n - 1}) = 10 - 6 = 4}[/tex]

  • Last term [tex]\rm{(a_n) = 38}[/tex]

» To find the sum of the series, we need to find the number of terms (n) at first. So,

  • [tex]\rm{a_n = a + (n - 1)d}[/tex]

  • [tex]\rm{38 = 6 + (n - 1)4}[/tex]

  • [tex]\rm{38 - 6 = 4n - 4}[/tex]

  • [tex]\rm{32 = 4n - 4}[/tex]

  • [tex]\rm{32 ÷ 4 = 4n}[/tex]

  • [tex]\rm{36 = 4n}[/tex]

  • [tex]\rm{36 ÷ 4 = n}[/tex]

  • [tex]\rm{9 = n}[/tex]

» Now, let's find the sum of the arithmetic series [tex]\rm{(S_n)}[/tex]:

  • [tex]\rm{S_n = \dfrac{n}{2}[2a + (n - 1)d]}[/tex]

  • [tex]\rm{S_n = \dfrac{9}{2}[2 × 6 ÷ (9 - 1)4]}[/tex]

  • [tex]\rm{S_n = \dfrac{9}{2}[12 + (8 × 4)]}[/tex]

  • [tex]\rm{S_n = \dfrac{9}{2}[12 + 32]}[/tex]

  • [tex]\rm{S_n = \dfrac{9}{2}(44)}[/tex]

  • [tex]\rm{S_n = 9 × 22}[/tex]

  • [tex]\rm{S_n = 198}[/tex]

=======================

#LearnWithBrainly

#CarryOnLearning