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solve the discriminant of 6x² - 2x - 1=0 then determine the nature of roots.​

Sagot :

Selene1225idn

Answer:

solve the discriminant of 6x² - 2x - 1=0 then determine the nature of roots.​

Step-by-step explanation:

meow me hopes it helps ya

MissJindySummeridn

[tex]\Large\color{aqua}\underline\mathbb{DISCRIMINANT}[/tex]

solve the discriminant of 6x² - 2x - 1 = 0 then determine the nature of roots.

[tex]\\[/tex]

To determine the discriminant, use the formula b² - 4ac. Identify first the values of a, b, and c by using the quadratic form ax² + bx + c = 0.

  • ax² + bx + c = 0
  • 6x² - 2x - 1 = 0
  • a = 6, b = -2, c = -1

-------------------------------------

  • b² - 4ac
  • (-2)² - 4(6)(-1)
  • 4 - 4(-6)
  • 4 + 24
  • 28

[tex]\\[/tex]

∴ Therefore, the discriminant is 28. Since i is greater than 0, it means it has two real roots.

[tex]\\[/tex]

[tex]\color{purple}\underline\mathbb{ANSWER:}[/tex]

  • Discriminant: 28
  • Nature of roots: Two real roots

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