Ronalddanganan83idn
Answered

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five boys and four girls are to arrange themselves to form a line. How many arrangements can there be if:

(a) the boys stand together, and the girls stand together?

(b) the boys and girls stand alternately?​

Sagot :

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Answer:

There are 5! = 120 arrangements for the boys, and 4! = 24 arrangements for the girls, and 2 possible orders (boys first or girls first). That gives a total of 120 × 24 × 2 = 5,760 possible arrangements.

Step-by-step explanation:

Its a question of permutation

There are 5 boys and 4 girls

Let boys be taken as 1 unit and all gorls be taken as 1 unit

Bothcof them can b arranged in 2P2 ways

Also boys internally arrange in 5P5 ways

And girls internally arrange as 4P4 ways

So total ways of aarangement be:

2P2 *5P5 *4P4=2*120*24=5760 ways

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