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360
This is a lesson about permutation.
There are choices, they are: 1, 3, 5, 6, 8, 9 (6 choices in all)
And we needed 4-digit numbers only.
Using the formula: [tex]_nP_r = \frac{n!}{(n-r)!}[/tex]
[tex]_6P_4 = \frac{6!}{(6-4)!}[/tex]
[tex]_6P_4 = \frac{6!}{2!}[/tex]
[tex]_6P_4 = \frac{6\times5\times4\times3\times2\times1}{2\times1}[/tex]
[tex]_6P_4 = 6\times5\times4\times3[/tex]
[tex]_6P_4 = 30\times4\times3[/tex]
[tex]_6P_4 = 120\times3[/tex]
[tex]_6P_4 = \bold{360}[/tex]
[tex]\red{ \huge{ \boxed{ \tt{{ ✨ANSWER✨ }}}}}[/tex]
[tex]\huge\red{\overline{\qquad\qquad\qquad\qquad \: \: \: }}[/tex]
Originally Answered: How many 4 digit even numbers can be formed from the digits 1, 3, 5, 6, 8 and 9 if repetition of digits is not allowed?
360 combinations. Originally Answered: How many four-digit numbers can be formed from the number 1, 3, 4, 6, 8, and 9 if repetition of digits
[tex]\huge\red{\overline{\qquad\qquad\qquad\qquad \: \: \: }}[/tex]
[tex]\huge\color{pink}\bold{-BELL-}[/tex]
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[tex] \huge\tt \color{pink}{HOPE IT HELPS!}[/tex]