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Solve the given problem, A pile of blocks has 40 blocks in the first row, 36 blocks in the second row, sa blocks on the third row and so on until there are only 4 blocks on the last row, 1. Make a table for the number of rows and blocks in the given problem. Rous Blocks 2. How many blocks are there in the 7th row? 3. In what row will there be 8 blocks? 4. How many blocks are there in all the first 4 rows? 5. Write the rule tom find the number of blocks in the nth row. 8​

Solve The Given Problem A Pile Of Blocks Has 40 Blocks In The First Row 36 Blocks In The Second Row Sa Blocks On The Third Row And So On Until There Are Only 4 class=

Sagot :

Answer:

1. 1st row = 40 blocks

  2nd row = 36 blocks

  3rd row = 32 blocks

  4th row = 28 blocks

2. 16 blocks

3. 9th row

4. 136 blocks

5. the rule is subtracting 4