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Sagot :
[tex]\color{red}\underline { \huge{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}[/tex]
[tex]\underline{\mathbb{SOLUTION}:} [/tex]
[tex]\sf \normalsize\:{ \: Determine \: the \: x- \: and \: y-intercept \: of \: \red{4x - y = 2}}[/tex]
[tex] \sf \: To \: determine \: the \: x - intercept, \: let \: y = 0 \:, then \: solve \: for \: the \: value \: of \: x . [/tex]
[tex]\sf \: 4x - y = 2[/tex]
- [tex] \sf \: 4x - 0 = 2[/tex]
- [tex] \sf \: 4x = 2[/tex]
- [tex] \large \sf \: \frac{4x}{4} = \frac{2}{4} [/tex]
- [tex] { \sf{x = \frac{2}{4} }} \: \sf \small{ or }\: \sf{ \normalsize \: { \frac{1}{2} }} \: \small{ or} \: \small \green{0.5}[/tex]
[tex]\therefore \sf \normalsize\: { As \: an \: ordered \: pair \: , it \: is \: written \: as \: \green { (0.5 , 0)}}[/tex]
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[tex]\sf \: To \: determine \: the \: y- intercept, \: let \: x = 0 \:, then \: solve \: for \: the \: value \: of \: y . [/tex]
[tex]\sf \: 4x - y = 2[/tex]
- [tex] \sf \: 4(0) - y = 2[/tex]
- [tex] \sf \: 0 - y = 2[/tex]
- [tex] \sf \: - y = 2[/tex]
- [tex] \large \sf \: \frac{ - y}{ - 1} = \frac{2}{1} [/tex]
- [tex] \sf \green {y = - 2}[/tex]
[tex]\therefore \sf \normalsize\: { As \: an \: ordered \: pair \: , it \: is \: written \: as \: \green{ (0 , - 2)}}[/tex]
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[tex] \sf \: On \: a \: cartesian \: plane, \: plot \: the \: points \: (0.5, 0) \: and (0,-2) \\ \sf Connect \: them \: to \: form \: the \: graph \: of \: 4x-y=2 [/tex]
[tex] \sf \: Determine \: the \: slope \: and \: the \: point \: on \: the \: line \: of \: y=4x+1. \\ \sf \: In \: the \: case, \: the \: slope \: (m) \: is \: 4. The \: slope \: can \: also \: be \: written \\ \sf \: \frac{rise}{run} , \: Hence, \: \frac{rise}{run} = \frac{4}{1}. \: The \: y-intercept \: (b) \: is \: 1. \: \\ \sf \: It \: is \: considered \: as \: the \: point \: on \: the \: line.[/tex]
[tex] \sf On \: the \: same \: cartesian \: plane, \: locate \: (0,1) \: which \: is \: the \: y-intercept. \\ \sf Use \:m=\frac{rise}{run} = \sf \: \frac{4}{1} . From \: (0,1) , \: count \:4 \: steps \: up \: for \: the \: 'rise' . \\ \sf \: This \: will \: lead \: us \: to \: (0,5). \: From \: (0,5), \: \: count \: one \: step \: to \sf the \: right \: for \: the \: 'run'. \: \\ \sf \: This \: will \: lead \: \: us \: to \: (1,5). \sf \: Connect \: \green{(0,1)} \: and \: \green{(1,5)} \: to \: form \: the \: graph of \: y=4x+1[/tex]
[tex] \sf \: The \: graph \: shows \: us \: parallel \: lines. \: Since \: the \: \: two \: lines \: did \: not \: intersect, \\ \sf there \: is \: no \: solution. \: This \: graph \: shows \: us \: an \: inconsistent.[/tex]
[tex]\color{red}\underline { \huge{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\: \: \: \: \: \: \: \: \: \: \: \: }}[/tex]
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