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Sagot :
Problem:
April is thrice as old as May. Five years from now the sum of their ages will be 114. Find their ages.
Solution:
In present age:
Let x be the May's age
Then let 3x be the April's age
In 7 yrs ago:
Five years ago from now, May's age
- x + 5
Five years ago from now, April's age
- 3x + 5
The sum of their ages will be 114.
- (May'age) + (April's age) = 114
- (x + 5) + (3x + 5) = 114
In equation:
- (x + 5) + (3x + 5) = 114
Solve the value of x which is the May's age to the problem equations.
- (x + 5) + (3x + 5) = 114
- 4x + 10 = 114
- 4x = 114 - 10
- 4x = 104
- 4x/4 = 104/4
- x = 26
Substitute the April's age to the present age which is the value of x to the solving the problem equation.
- April's age = 3x + 5
- April's age = 3(26) + 5
- April's age = 78 + 5
- April's age = 83
Checking:
Checking the age's if the answer is correct. If the May is 26 years old and April is 83 years old.
- (May'age) + (April's age) = 114
- (x + 5) + (3x + 5) = 114
- (26 + 5) + (3(26) + 5) = 114
- 31 + (78 + 5) = 114
- 31 + 83 = 114
- 114 = 114 ✔
Answer:
∴ Therefore, the present age of May is 26 years old and April is 83 years old.
P.S: Please click on the image above to see the age's table
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