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Sagot :
Speed (velocity) depends on distance and time travel
Further explanation
Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
At constant velocity motion:
the speed of vo = v = constant
acceleration = a = 0
Δx = vt or x = xo + vt
An equation of constant velocity motion
[tex]\rm D=v\times t[/tex]
D =distance , m
v = velocity, m/s
t = time, s
1. speed = v= 60 mph, t = 6 hours
[tex]\rm D=60\times 6=\boxed{\bold{360~miles}}[/tex]
2. distance = d =480 miles, t = 8 hours
[tex]\rm v=\dfrac{480}{8}=\boxed{\bold{6~mph}}[/tex]
3. speed = v = 3 mph, d = 24 miles
[tex]\rm t=\dfrac{24}{3}=\boxed{\bold{8~hours}}[/tex]
4. speed = v = 65 mph, t = 4 hours
[tex]\rm d=65\times 4=\boxed{\bold{260~miles}}[/tex]
5. speed = v = 6 mph, t = 4 hours
[tex]\rm d=6\times 3 =\boxed{\bold{18~miles}}[/tex]
6. d = 30 miles, v = 10 mph, initial time = 2:00 pm
[tex]\rm t=\dfrac{30}{10}=3~hours[/tex]
time arrive :
[tex]\rm 2:00~pm+3~hours=\boxed{\bold{5:00~pm}}[/tex]
Learn more
uniformly accelerated motion
https://brainly.ph/question/2132892
https://brainly.ph/question/2088325
the probe’s velocity relative to the earth
https://brainly.ph/question/1467317
Uniformly accelerated motion: vertical dimension
https://brainly.ph/question/2098492
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