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six rectangles each with a common base width of 2 have lengths of 1,4,9,16,25, and 36. What is the sum of the areas of the six rectangles?

Sagot :

The area of a rectangle is L x W  or A = w l.
Given: six rectangles with the lengths of 1,4,9,16, 25, and 36
all six has the base width of 2
Let all 6 rectangles be, R1, R2, R3, R4, R5, and R6
R1
R1=L x W
    = 1 x 2
R1 = 2

R2
R2 = L x W
     = 4 x 2
R2 = 8

R3
R3 = L x W
     = 9 x 2
R3 = 18

R4

R4= L x W
    = 16 x 2
R4 = 32

R5
R5 = L x W
     = 25 x 2
 R5 = 50

R6
R6 = L x W
     = 36 x 2
 R6 = 72

Total sum of areas = R1+ R2 +  R3 + R4 + R5 + R6
                           = 2 + 8 +18 + 32 + 50 + 72
Total sum of areas = 182