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Six rectangles each with a common base width of 2 have lengths of 1,4,9,16,25, and 36. What is the sum of the areas of the six rectangles?

Sagot :

The sum of the areas is equal to 2∗1+2∗4+2∗9+2∗16+2∗25+2∗36  . This is simply equal to 2∗(1+4+9+16+25+36)  , which is equal to 2∗91  , which is equal to our final answer of 182