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whats the answer of (Log₃9) and 2log?

Sagot :

log₃9 = 2 
(because 3² = 9)

2log can not be answered because it's incomplete. It doesn't have the larger number.
log₃9 = y

According to the Rule of Logarithms, if log(b)x = y then x = b^y
Applying the rule to your problem:
9 = 3^y
3^2 = 3^y Then by one-to-one correspondence,

y = 2

What do you want to do with 2log? I believe you've yyped it wrong ;)