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what is the mass of 1.464mol of calcium phosphate?

Sagot :

Calcium Phosphate is [tex]Ca _{3} (PO _{4} ) _{2} [/tex] = [tex]Ca _{3} P _{2} O _{8} [/tex]

Multiply the atomic mass of each element by its subscript, then add the result:
Calcium = 3 (40.08) = 120.24 g/mol
Phosphorous = 2 (30.974) = 61.95 g/mol
Oxygen = 8 (16) = 128 g/mol

(120.24 + 61.95 + 128) g/mole = 310.19 g/mol

Multiply the sum by 1.464 mol:

1.464 mol x 310.19 g/mol = 454.1186 g.