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Given: W varies jointly with X and the square of Y when W=90, X=5 and Y=3.
[tex]\Large \blue{\bold{k = 6 \: and \: the \: equation \: of}} \\ \Large \blue{\bold{variation \: is \: W = 6XY}}[/tex]
Step 1: Write the correct equation. Joint variation problems are solved using the equation x=kzy if x varies jointly as z and y.
[tex]\large \bold{W=kXY}[/tex]
Step 2: Use the information given in the problem to find the value of k. In this case, you need to find k if W=90, X=5 and Y=3.
[tex]W = kXY \\ 90 = k(5)(3) \\ 90=15k \\ \frac{90}{15} = \frac{ \cancel{15}k}{ \cancel{15}} \\ \bold{6 = k}[/tex]
Therefore, the constant of variation k is 6.