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A featured film promoting entrepreneurship sold a total of 282 tickets. Tickets were priced at 75 Pesos for students and 100 Pesos for nonstudents. If the amount collected from the tickets was 22,450 Pesos, How many tickets of each kind were sold? Solution and answer, please.

Sagot :

Step-by-step explanation:

Given:

Tickets sold = 282 tickets

Ticket sales = ₱ 22,450.00

Student = ₱75.00

Non-student = ₱100.00

Solution:

Let x = number of student tickets

Let y = number of non-student tickets

Total tickets sold = students + non- students

x + y = 282 ---> Equation 1

Total ticket sales = quantity x cost

75x + 100y = 22,450 ---> Equation 2

Isolate variable x in Equation 1

x + y = 282

x = 282 - y ---> Equation 3

Substitute Equation 3 in Equation 2

75x + 100y = 22,450

75(282 - y) + 100y = 22,450

21,150 - 75y + 100y = 22,450

-75y + 100y = 22,450 - 21,150

25y = 1300

[tex] \frac{25y}{25} = \frac{1300}{25} [/tex]

y = 52

Substitute y = 52 into Equation 1

x + y = 282

x + 52 = 282

x = 282 - 52

x = 230

Answer:

230 tickets for students and 52 tickets for non-students were sold.