Answer:
The volume of this gas : 0.52 L
Further explanation
Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated), among others
Boyle's law at constant T, P = 1 / V
Charles's law, at constant P, V = T
Avogadro's law, at constant P and T, V = n
So that the three laws can be combined into a single gas equation, the ideal gas equation
\rm PV=nRTPV=nRT
In Boyle's law, it is stated that
In a closed system, the absolute pressure by an ideal gas is inversely proportional to the volume it occupies if the temperature is constant
So it can be stated
\rm \large{\boxed{\bold{P_1.V_1=P_2.V_2}}
A gas occupies 1.56 L at 1.00 atm. and the pressure becomes 3.00 atm
So :
Initial conditions:
P₁ = 1 atm
V₁ = 1.56 L
Final conditions
P₂ = 3 atm
The volume of this gas (V₂) :
\begin{gathered}\rm V_2=\dfrac{P_1.V_1}{P_2}\\\\V_2=\dfrac{1\times 1.56}{3}\\\\V_2=\boxed{\bold{0.52~L}}\end{gathered}
V
2
=
P
2
P
1
.V
1
V
2
=
3
1×1.56
V
2
=
0.52 L
