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guided practice 2 show the solution​

Guided Practice 2 Show The Solution class=

Sagot :

Proportion

Directions: Find the missing term in the following proportions. Use Cross-Product Rule. Check your answer.

  • 1) 12:n = 36:15

Solution:

Make it Fraction

[tex] \frac{12}{n} = \frac{36}{15} [/tex]

Use Cross Product Rule

[tex] \frac{12 \times 15}{36 \times n} = 180 = 36n [/tex]

Divide both sides by 36

[tex]\frac{180}{36} = \frac{\cancel{36}n}{\cancel{36}} [/tex]

[tex]\large\tt\color{blue}\boxed{n = 5}[/tex]

  • 2) n:10 = 12:40

Solution:

Make it Fraction

[tex]\frac{n}{10}=\frac{12}{40}[/tex]

Use Cross Product Rule

[tex]\frac{n×40}{10×12}=40n=120[/tex]

Divide both sides by 40

[tex]\frac{\cancel{40}n}{\cancel{40}}=\frac{120}{40}[/tex]

[tex]\large\tt\color{blue}\boxed{n=3}[/tex]

  • 3) 7:2 = 21:n

Solution:

Make it Fraction

[tex]\frac{7}{2}=\frac{21}{n}[/tex]

Use Cross Product Rule

[tex]\frac{7×n}{2×21}=7n=42[/tex]

Divide both sides by 7

[tex]\frac{\cancel{7}n}{\cancel{7}}=\frac{42}{7}[/tex]

[tex]\large\tt\color{blue}\boxed{n=6}[/tex]

  • 4) [tex] \frac{20}{3} = \frac{40}{n} [/tex]

Use Cross Product Rule

[tex]\frac{20×n}{3×40} = 20n=120[/tex]

Divide both sides by 20

[tex]\frac{\cancel{20}n}{\cancel{20}}= \frac{120}{20}[/tex]

[tex]\large\tt\color{blue}\boxed{n=6}[/tex]

  • 5) [tex] \frac{36}{40} = \frac{9}{n} [/tex]

Use Cross Product Rule

[tex]\frac{36×n}{40×9}=36n=360[/tex]

Divide both sides by 36

[tex]\frac{\cancel{36}n}{\cancel{36}}=\frac{360}{36}[/tex]

[tex]\large\tt\color{blue}\boxed{n=10}[/tex]

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