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what is the percent composition by mass of aspartame (C14H18N2O5) the artificial sweetener​

Sagot :

Answer:

I will solve for percentage composition of

N

in the compound.

Explanation:

Molecular mass of aspartame:

=

(

14

×

12.011

+

18

×

1.00794

+

2

×

14.011

+

5

×

15.999

)

g

m

o

l

1

=

294.31

g

m

o

l

1

.

But we want the percentage composition of nitrogen in the sample:

2

×

14.011

g

m

o

l

1

294.31

g

m

o

l

1

×

100

%

=

?

?

%

Note that the sum of the individual elemental percentages must equal 100%