Heeseung2565idn
Answered

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the sum of three consecutive negative odd integers is -33 what is the difference if you are going to subtract the smallest integer from the biggest integer?​

pa help po ngayon na po pasahan namin TwT

Sagot :

KAntoineDoixidn

✒️INTEGERS

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[tex] \large\underline{\mathbb{ANSWER}:} [/tex]

[tex] \qquad \Large \:\: \rm The \: difference \: is \: 4 [/tex]

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[tex] \large\underline{\mathbb{SOLUTION}:} [/tex]

Let x be the first consecutive negative odd integer then deter the rest.

  • [tex] \rm 1st = \mathcal{x} [/tex]
  • [tex] \rm 2nd = \mathcal{x + 2} [/tex]
  • [tex] \rm 3rd = \mathcal{x + 4} [/tex]

Find the value of x if their sum is -33.

  • [tex] x + (x + 2) + (x + 4) = \text-33 [/tex]

  • [tex] x + x + 2 + x + 4 = \text-33 [/tex]

  • [tex] x + x + x + 2 + 4 = \text-33 [/tex]

  • [tex] 3x + 6 = \text-33 [/tex]

  • [tex] 3x = \text-33 - 6 [/tex]

  • [tex] 3x = \text-39 [/tex]

  • [tex] \frac{3x}3 = \frac{\text-39}3 \\ [/tex]

  • [tex] x = \text-13 [/tex]

Therefore, the value of x or the first consecutive integer is -13. Find the others.

  • [tex] \rm 1st = \mathcal{\text-13} [/tex]
  • [tex] \rm 2nd = \mathcal{\text-13 + 2} [/tex]
  • [tex] \rm 3rd = \mathcal{\text-13 + 4} [/tex]

  • [tex] \rm 1st = \mathcal{\text-13} [/tex]
  • [tex] \rm 2nd = \mathcal{\text-11} [/tex]
  • [tex] \rm 3rd = \mathcal{\text-9} [/tex]

Find the difference between the larger integer and the smaller integer which are the numbers -9 and -13, respectively.

  • [tex] \implies (\text-9) - (\text-13) [/tex]

  • [tex] \implies \text-9 + 13 [/tex]

  • [tex] \implies 4 [/tex]

Therefore, the difference between the negative integers is 4.

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