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➣ Solution for number 6:
Given Series:
5, 8, 11, 54, ...
a = 5, d = 8 - 5 = 3
So, t₂₇ = a + (n - 1)d
= 5 + (27 - 1)(3)
= 5 + 26 × 3
= 83
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➣ Solution for number 7:
Given sequence:
2, 5, 8, 11, ...
Here, First term: a = 2
Number of terms: n = 40
Common difference: d = 3
So, The 40th term is,
t₄₀ = a + (n - 1)d
= 2 + (40 - 1)(3)
= 2 + 39 × 3
= 119
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➣ Solution for number 8:
Given Series:
7, 13, 19, 25, ...
Here, a = 7, d = 13 - 7 = 6
16th term, t₁₆ = a + (n - 1)d
= 7 + (16 - 1)6
= 7 + 90
= 97
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