Pat1415idn
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Pls help me i need to answer this​

Pls Help Me I Need To Answer This class=

Sagot :

InfinityERidn

Answer:

B.

1. 82x-2

2. 8a^3+9a^2-80a-90

3.-12p^4 + 64p^3 + 16p^2

C.

1. 13 r. 0

2. 4x^2-6x+2 l x

3. 6x^3- 16x^2 - 64x / 3 r. 7

Pa brainliest thanks

Annalyncapistrano688idn

[tex] \huge \mathtt { Answer :}[/tex]

B. Simplify

1.) 82x - 2

2.) 8a³ + 9a² - 80a - 90

3.) -12p⁴ + 64p³ + 16p²

Solution and C.☟

[tex] \huge \color{red}{❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉}[/tex]

1.) 82x - 2

Solution :

》Simplify or Expand☟

[tex]{6( 7x + 5 ) + 4( 10x - 8 )}[/tex]

Apply the diatributive property = [tex]{6( 7x + 5 )}[/tex] ☟

[tex]{(6 × 7x + 6 × 5) + 4( 10x - 8)}[/tex]

Apply the diatributive property = [tex]{4( 10x - 8 )}[/tex]☟

[tex]{(6 × 7x + 6 × 5) + (4 × 10x - 4 × 8)}[/tex]

Multiply the monomials.= [tex]{4 × 10x}[/tex]

[tex]{(6 × 7x + 6 × 5) + (40x - 4 × 8)}[/tex]

Multiply the monomials.= [tex]{6 × 7x}[/tex]

[tex]{( 42x + 6 × 5) + 40x - 4 × 8}[/tex]

Calculate the product or quotient = [tex]{6 × 5}[/tex]

[tex]{( 42x + 30) + 40x - 4 × 8}[/tex]

Calculate the product or quotient = [tex]{4 × 8}[/tex]

[tex]{( 42x + 30) + 40x - 32}[/tex]

Reorder and gutter like terms

[tex]{( 42x + 40x) + (30 - 32)}[/tex]

Collect coefficients of like terms

[tex]{( 42 + 40) + x + (30 - 32)}[/tex]

"Now calculate the sum or difference"

Final answer : 82x - 2

2.) 8a³ + 9a² - 80a - 90

Solution :

》Simplify or Expand☟

[tex]{a²(8a + 9) - 10(8a + 9)}[/tex]

Apply the diatributive property =a²(8a + 9)☟

[tex]{(a² × 8a + a² × 9) - 10(8a + 9)}[/tex]

Apply the diatributive property =10(8a + 9)☟

[tex]{(a² × 8a + a² × 9) - (10 × 8a - 10 × 9)}[/tex]

Multiply the monomials.= a² × 8a

[tex]{(8a³ + a² × 9) - (10 × 8a - 10 × 9)}[/tex]

Multiply the monomials.= a² × 9

[tex]{(8a³ + 9a²) - (10 × 8a - 10 × 9)}[/tex]

Multiply the monomials.= -10 × 8a

[tex]{(8a³ + 9a²) - (80a - 10 × 9)}[/tex]

Calculate the product or quotient = 10 × 9

[tex]{(8a³ + 9a²) - (80a - 90)}[/tex]

Final answer : 8a³ + 9a² - 80a - 90

3.) -12p⁴ + 64p³ + 16p²

na tamad nako pakita ung solution

[tex] \huge \color{red}{❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉}[/tex]

C. Complete the table

1.) Quotient = 13 Remainder = 0

2.) Quoteint = 4x+4 Remainder = 10

3.) Quotient = 2x-10 Remainder = 6

[tex] \huge \color{red}{❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉❉}[/tex]

Hope it helps:)

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