Ashleymaeppoyicaridn
Answered

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The rate of heat transferred varies jointly with the cross-sectional area of the material transferring heat and the temperature difference between one side of the material and the other. It also varies Inversely with the thickness of the material. The rate of heat transferred through a window is 480 W. The cross-sectional area of the window is 3 m and its thickness is 0.05 m. The temperature difference Inside and outside is 10k. If the area of the window is 3.75 m and its thickness is 0.06 m. and temperature difference is 8k, how much is the rate of heat transferred? ​

Sagot :

Avillaluzidn

Let H be the rate of heat transfer

A = cross sectional area

T = temperature difference

t = thickness

k = constant

H = kAT / t

480 = k (3)(10)/0.05

k = (480)(0.05)/30 = 0.8

Get H when A=3.75, t=0.06, T=8

H = kAT / t

= (0.8)(3.75)(8)/0.06

H = 400 W

OR just use proportions, since k is the same for both situations:

k = Ht / AT

H1 t1 / A1 T1 = H2 t2 / A2 T2

(480)(0.05) / (3)(10) = (H2)(0.06)/(3.75)(8)

H2 = (480)(0.05)(3.75)(8) / (3)(10)(0.06)

= 400W

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