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twice the number of marbles in bag A is less tha the number of marbles in bag b. the sum of the number of marbles in bags A and C is less than the number of marbles in bag b. there are more marbles i bag d than in bg b .There ar 6 marbles in bag C and 9 marbles in bag D. how many marbles does bag b contain

Sagot :

AwesomeHelperidn
2a < b 
a + c < b
d > b

Given:
6c and 9d 

b = ?

Substituting using the given:
2a < b 
a + 6 < b
9 > b

Solve
If a = 1
2(1) < b
1 + 6 < b
9 > b

2 < b
7 < b
9 > b

The bag b contains 8 marbles.

Check:
2 (a * 2) < 8 (b)
1 (a) + 6 (c) < 8 (b)
9 (d) < 8 (b)
NOTE: DON'T MIND THE PARENTHESES, JUST TO INDICATE THE LETTER OF THE BOX.

So therefore, totally there are 8 marbles in bag b. 
Bag A = 1 MARBLE
Bag B = 8 MARBLES
Bag C = 6 MARBLES
Bag D = 9 MARBLES

2(1) < 8 = Twice (2) the number of marbles in bag A (1) is less than (<) the                    number of marbles in bag B (8) which is true. 
1 + 6 < 8 = The sum (+) of the number of marbles in bag A (1) and bag C (6)                  is less than (<) the number of marbles in bag B (8) which is true.
9 > 8 = There are more marbles in bag D (9) than in bag B (8) which is true.

So therefore, 8 is our answer. The Bag B contains 8 marbles at all. 



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