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pa help po ulit ng assignment ko sa geometry...  Thank you po :))

Steps:
A. Draw a triangle in a cartesian plane.
B. Name the vertices.
C. Solve for the slope of side 1, side 2, and side 3 of a triangle.
D. Solve the distance of side 1,side 2 and side 3.
E. Solve the interior angles of the vertices..



Sagot :

C. [tex]m = \frac{y_{1}- y_{0}}{x_{1}- x_{0}}[/tex]

slope of line AB: [tex]m = \frac{2-0}{0 - (-2)} = \frac{2}{2} = 1[/tex]

slope of line BC: [tex]m = \frac{0-0}{-2 - 1} = 0[/tex]

slope of line AC: [tex]m = \frac{2-0}{0 - 1} = -2[/tex]


D. [tex]distance = \sqrt{(y_{1}-y_{0})^{2} + (x_{1}-x_{0})^{2}} [/tex]

distance from A to B [tex]= \sqrt{(2-0)^{2} + (0-(-2))^{2}} = \sqrt{2^{2} + 2^{2}} = \sqrt{8} = 2 \sqrt{2} [/tex]

distance from B to C [tex]= \sqrt{(0-0)^{2} + ((-2)-(1))^{2}} = \sqrt{3^{2}} = 3 [/tex]

distance form A to C [tex]= \sqrt{(2-0)^{2} + (0-1)^{2}} = \sqrt{2^{2} + 1^{2}} = \sqrt{5}[/tex]
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