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give the quadratic functions y=x2 - 2x - 3 and y = -x2 + 4x - 1, transform them into the form y=a(x-h)2+k.

Sagot :

vertex of parabola/graph of quadratic equation = (h,k)

h = -b/2a
k = 4ac - b²
        4a

1) y = x² - 2x - 3
   a = 1;   b = -2;   c= -3

    h = -(-2)/ 2(1)
    h = 2/2
    h = 1
   
    k = 4ac - b²
              4a
    k = 4(1)(-3) - (-2)²
             4(1)
    k = - 12 - 4
            4
    k = -16/4
    k = - 4
    
   Vertex form : a (x-h)² + k,  substitute the values for h and k:

   Vertex form: a(x-1)² - 4

2) -x² + 4x-1
   a = -1;   b = 4;    c= -1
    
  h = -(4)/2(-1)
  h = -4/-2
  h = 2
   
  k = 4(-1)(-1) - (4)²
            4(-1)
  k = 4 - 16
          -4
  k = -12/-4
  k = 3
  
  Vertex form:  Substitute the values for h and k:

  Vertex form:  - (x-2)² + 3