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Adding twice a number to its quad, we get 234. What is this number?​

Sagot :

GreatNiclausidn

✒️[tex]\large{\mathcal{ANSWER}}[/tex]

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  • The number that corresponds to this question , where : "Adding the double of a number to its quadruple , we get 234" , is equal to : 39 .

To solve this problem, we will calculate it as a first degree equation, thus identifying its algebraic terms.

● The data for this question being:

  • adding twice → 2x +
  • to your quad → 4x
  • we get 234 → 234

So, the assembled equation will be:

[tex]2x + 4x = 234[/tex]

• Add the equal terms to the right side of the equality. Then isolate "x" and divide the second into the first member of the equation:

[tex]2x + 4x = 234[/tex]

[tex](2 + 4)x = 234[/tex]

[tex]6x = 234[/tex]

[tex]x = 234 \div 6[/tex]

[tex]x = 234 \div 6 = \frac{234}{6} [/tex]

[tex] \: \boxed{x = 39} [/tex]

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● Therefore, we can conclude that the correct value of this number is equal to: 39.

[tex] \: \boxed{x = 39} [/tex]

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