Suriin ang IDNStudy.com para sa mabilis at maaasahang mga solusyon. Sumali sa aming platform upang makatanggap ng mabilis at eksaktong tugon mula sa mga propesyonal sa iba't ibang larangan.

B. Find the length of the unknown segment (x) in each of the following figures.​

B Find The Length Of The Unknown Segment X In Each Of The Following Figures class=

Sagot :

✒️POWER THEOREMS

[tex]••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]

[tex] \large\underline{\mathbb{ANSWERS}:} [/tex]

[tex] \qquad \Large \:\: \rm{1) \; x = 10.5 \: units} [/tex]

[tex] \qquad \Large \:\: \rm{2) \; x = 4 \: units} [/tex]

[tex] \qquad \Large \:\: \rm{3) \; x = 9 \: units} [/tex]

[tex]••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]

[tex] \large\underline{\mathbb{SOLUTIONS}:} [/tex]

#1: By according to the Chord-Chord Power Theorem, the given suggests that:

  • [tex] (ON)(NA) = (RN)(NM) [/tex]

» Substitute the given and then find x.

  • [tex] (8)(x) = (12)(7) [/tex]

  • [tex] 8x = 84 [/tex]

  • [tex] \frac{\,8x\,}{8} = \frac{\,84\,}{8} \\ [/tex]

  • [tex] x = 10.5 [/tex]

[tex] \therefore [/tex] The length of segment x is 10.5 units

[tex] \: [/tex]

#2: By according to the Tangent-Secant Power Theorem, the given suggests that:

  • [tex] (VE)^2 = (VL)(VO) [/tex]

» Substitute the given and then find x.

  • [tex] (10)^2 = (25)(x) [/tex]

  • [tex] 100 = 25x [/tex]

  • [tex] \frac{\,100\,}{25} = \frac{\,25x\,}{25} \\ [/tex]

  • [tex] 4 = x [/tex]

[tex] \therefore [/tex] The length of segment x is 4 units

[tex] \: [/tex]

#3: By according to the Secant-Secant Power Theorem, the given suggests that:

  • [tex] (IS)(IH) = (IT)(IF) [/tex]

  • [tex] (IS)(IH) = (IF + FT)(IF) [/tex]

» Substitute the given and then find x.

  • [tex] (16)(x) = (8 + 10)(8) [/tex]

  • [tex] (16)(x) = (18)(8) [/tex]

  • [tex] 16x = 144 [/tex]

  • [tex] \frac{\,16x\,}{16} = \frac{\,144\,}{16} \\ [/tex]

  • [tex] x = 9 [/tex]

[tex] \therefore [/tex] The length of segment x is 9 units

[tex]••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]

(ノ^_^)ノ