Moon999idn
Answered

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possible roots and actual roots

2) . 2x³-x²-x+1=0

3) .x4 -5x²+4=0

4). 2x4 -7x³-4x+27x-18=0​

Sagot :

Alysonjanegobeidn

2. x=−0.829484

3. x=±2,±1

4.x=−1.773013,1

Step-by-step explanation:

2. sullution

step 1:No root was found algebraically. However, the following root(s) were found by numerical methods.

x=-0.829484

3. sullution

step 1: Factor {x}^{4}-5{x}^{2}+4x

4

−5x

2

+4.

({x}^{2}-4)({x}^{2}-1)=0

(x

2

−4)(x

2

−1)=0

step 2: Solve for x.

x=\pm 2,\pm 1

x=±2,±1

4. Sollution

step 1: Simplify 2{x}^{4}-7{x}^{3}-4x+27x-182x

4

−7x

3

−4x+27x−18 to 2{x}^{4}-7{x}^{3}+23x-182x

4

−7x

3

+23x−18.

2{x}^{4}-7{x}^{3}+23x-18=0

2x

4

−7x

3

+23x−18=0

step 2: Factor 2{x}^{4}-7{x}^{3}+23x-182x

4

−7x

3

+23x−18 using Polynomial Division.

(2{x}^{3}-5{x}^{2}-5x+18)(x-1)=0

(2x

3

−5x

2

−5x+18)(x−1)=0

step 3: No root was found algebraically. However, the following root(s) were found by numerical methods.

x=-1.773013,1

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