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1.what must be added to obtain 10a
2.Simplify: 26 p + w + r + 4q + 5r
3.the length of the rectangle is ( 3x + 2 ) cm and its width is ( 2x - 1 ) cm. Express the perimeter of the rectangle in simplest form​


Sagot :

Answer:

1. - 13a

3a + x = -10a

x = -10a - 3a

x = -13a

Therefore, 3a + -13a = -10a

2. Answer :26p + 4q + 6r + w

3. Solution

Verified by Toppr

Let length of rectangle- Icm

breadth of rectangle = bcm

Given length is 3 times its breadth i.e. 1 = 3 × b

Perimeter of the rectangle 120 cm

i.e.2 x (1 + b) = 120

2x (3 × b + b) = 120 2x (4x b) = 120

8 × b = 120

b= 15 cm

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