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Sagot :

JuliaSlodavaidn

[tex]\large\underline{\rm\color {black}{DIRECTIONS}:}[/tex]

  • Use the figure and the given information to answer the questions that follow. Explain how you arrived at your answer.

[tex]\tt\color{maroon}{===========================================}[/tex]

[tex]\large\underline{\rm\color {black}{PROBLEM}:}[/tex]

  • If mADC = 160 and mEF = 80, what is m<ABC?

[tex]\tt\color{maroon}{===========================================}[/tex]

[tex]\large\underline{\rm\color {black}{ANSWER}:}[/tex]

  • [tex]\large\underline\color{yellowgreen} {{\tt{m<ABC \: ≈ \: 40°}}}[/tex]

[tex]\tt\color{maroon}{===========================================}[/tex]

[tex]\sf\underline\color {black}{FORMULA:}[/tex]

  • [tex]\small\bold\color {white}{m<ABC \: = \: \frac{mADC \: - \: mEF}{2} }[/tex]

[tex]\tt\color{maroon}{===========================================}[/tex]

[tex]\large\underline{\rm\color {black}{SOLUTION}:}[/tex]

  • [tex]\small\bold\color {white}{m<ABC \: = \: \frac{mADC \: - \: mEF}{2} }[/tex]

  • [tex]\small\bold\color {white}{m<ABC \: = } \: \frac{160 \: - \: 80}{ 2} [/tex]

  • [tex]\small\bold\color {white}{m<ABC \: = \: \frac{80}{2} }[/tex]

  • [tex]\small\bold\color {white}{m<ABC \: = 40°}[/tex]

⟹ Hence, the measure of m<ABC is 40°.

[tex]\tt\color{maroon}{===========================================}[/tex]

[tex]\tiny\color{darkorange} {{\tt{CarryOnLearning:)}}}[/tex]

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