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PROBLEM:
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ANSWER:
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SOLUTION:
[tex]\large{ \tt \red{Given:}}\\\small{ \tt \purple{Area =3x^2+7x+6}}\\\small{ \tt \purple{Width=(x+3)}}\\\small{ \tt \purple{Length:\:?}}[/tex]
[tex]\small{ \tt \purple{3x^2+7x+6}}\\\small{ \tt \purple{3x^2+9x-2x-6}}\\\small{ \tt \purple{3x(x+3)-2(x+3)}}\\\small{ \tt \purple{(3x-2)(x+3)}}\\\\\small{ \tt \purple{The\:width\:is=(x+3)}}\\\small{ \tt \purple{The\:length\:is=(3x-2)}}[/tex]
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