IDNStudy.com, ang iyong mapagkukunan ng eksaktong at maaasahang mga sagot. Anuman ang kahirapan ng iyong mga tanong, ang aming komunidad ay may mga sagot na kailangan mo.

the area of the rectangle is 3ײ +7×+6what is the length if the width is (x+3) ​

Sagot :

PROBLEM:

  • the area of the rectangle is 3x² +7x + 6 what is the length if the width is (x + 3). ​

_____________________

ANSWER:

  • [tex]{\large{\underline{\boxed{\sf{\red{Length= (3x-2)}}}}}}[/tex]

_____________________

SOLUTION:

[tex]\large{ \tt \red{Given:}}\\\small{ \tt \purple{Area =3x^2+7x+6}}\\\small{ \tt \purple{Width=(x+3)}}\\\small{ \tt \purple{Length:\:?}}[/tex]

[tex]\small{ \tt \purple{3x^2+7x+6}}\\\small{ \tt \purple{3x^2+9x-2x-6}}\\\small{ \tt \purple{3x(x+3)-2(x+3)}}\\\small{ \tt \purple{(3x-2)(x+3)}}\\\\\small{ \tt \purple{The\:width\:is=(x+3)}}\\\small{ \tt \purple{The\:length\:is=(3x-2)}}[/tex]

_____________________

   #CarryOnLearning