Answer:
Correct option is A)
Given,
Size of object h
o
=5cm
Size of the image h
i
=?
Focal length, f=−10cm
Object distance u=−60cm
Image distance v=?
Using mirror formula,
f
1
=
v
1
+
u
1
−10
1
=
v
1
+
−60
1
v
1
=
60
−6+1
v=−12cm
Hence, the position of the object is at 12 cm in front of the mirror.
Magnification (M)=
h
o
h
i
=
u
−v
=
−60
12
=−0.2
h
i
=−0.2×h
o
h
i
=−0.2×5=−1cm
Height of inverted image is 1cm.
