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4/5 raise to 0
[tex] \frac{4}{5} ^{0} [/tex]
pasagot po ng maayus...
thank you in advance​

Sagot :

GreatNiclausidn

✒️[tex]\large{\mathcal{ANSWER}}[/tex]

[tex]======================[/tex]

Calculating, we're going to get: 1, right, but... Why?! It's very simple, enough more, I'll explain.

We have the base, exponent and potency/product. Being them:

  • Base >> Number that multiplies.
  • Exponent >> Number we use to multiply.
  • Power/product >> Result of our enhancement.

For example: 2³ = 2 x 2 x 2 = 8

  • Base >> 2
  • Exponent >> 3
  • Power/product >> 8

In the potentiation if the exponent is 0, the result will be 1.

  • For example; 6° = 1

What if the exponent is like 1? Well, the result will be the same as presented in the base, as any number multiplied by 1 holds.

  • For example; 5¹ = 5

What if it's the other way around? What if the base equals 1? The result will also be 1, it's almost the same rule as above.

  • For example; 1² = 1

What if the base is negative with a positive even exponent? The result will be positive.

  • For example; (-5)² = 5² = 5 × 5 = 25

If base is negative with positive odd exponent? Then the result will be negative.

  • For example; (-5)³ = -5³ = -(5 x 5 x 5) -125

What if the base is fractional? We're going to have to raise the numerator and denominator to the exponent.

  • For example;[tex]( \frac{1}{2} ) {}^{2} = \frac{ {1}^{2} }{ {2}^{2} } = \frac{1}{4} [/tex]

[tex]−−−−−−−✠−−−−−−−[/tex]