Sammyjimena7idn
Answered

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Mr. Cruz has 84 biscuits and 56 packs of juice. He wants to share them equally with all of his students. What is the highest possible number of students does Mr. Cruz have in his class? A. What is asked in the problem? B. What facts are given? C. What is/are the key word/s webol D. How will you solve the problem? no E. What is the answer to the problem? no​

Sagot :

Answer:

A. the highest possible number of students does Mr. Cruz have in his class

B. 84 biscuits and 56 packs of juice

C. Share

D. 56÷2=28 thus 84-56=28

E. Mr. Cruz has possible 28 students in his class.

Step-by-step explanation:

This problem is kinda confusing, if you want to understand this seriously, then retake the fundamentals of problem solving.

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