IDNStudy.com, ang iyong pangunahing mapagkukunan para sa mga sagot ng eksperto. Ang aming komunidad ay handang magbigay ng malalim at praktikal na mga solusyon sa lahat ng iyong mga katanungan.

Find three consecutive numbers whose sum is 36.

solution please?​


Sagot :

✒MATHEMATICS

SOLUTION:

Write the place value of the following digits in the numeral 437.218

Let the three consecutive number are n , n + 1 , n + 2.

So,

  • n + (n + 1) + (n + 2) = 36
  • 3n + 3 = 36
  • 3n = 36 - 3
  • n = 33/3
  • n = [tex]{\boxed{\green{\sf{11 }}}}[/tex]

then solve for three consecutive,

  • (i) n = [tex]{\boxed{\green{\sf{11 }}}}[/tex]
  • (ii) n + 1 = 11 + 1 = [tex]{\boxed{\green{\sf{12 }}}}[/tex]
  • (iii) n + 2 = 11 + 2 = [tex]{\boxed{\green{\sf{13 }}}}[/tex]

ANSWER :

  • Therefore, the three consecutive numbers whose sum is 36 are 11, 12 and 13.

hope this helps

#CarryOnLearning

Answer:

Three consecutive integers whose sum is 36 are 11, 12, and 13.

Step-by-step explanation:

Let the three consecutive numbers be :

( x ),( x+1 ), ( x+2 )

As per the condition given:

(x)+(x+1)+(x+2)=36

3x+3=36

3x=36

x=11

So the numbers are as follows: 11,12,13