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Solve the following problems.Write the solutions in your Yellow Pad Paper​

Solve The Following ProblemsWrite The Solutions In Your Yellow Pad Paper class=

Sagot :

Answers/Solutions:

26.) 17ab² - 3ab

First, subtract (-5a²b+7ab²) and (a²b+9ab²).

-5a²b+7ab² - a²b + 9ab² =

(-5a²b - a²b) + (7ab² + 9ab²) =

-4a²b + 16ab²→ difference

Then, we must add the difference from 4a²b - 3ab + ab².

(4a²b - 3ab + ab²) + (-4a²b + 16ab²) =

(4a²b - 4a²b) -3ab + (ab² + 16ab²) =

-3ab + 17ab²

Final Answer: 17ab² - 3ab

27.) 3x² + 7y² + 26

First, add (7x² + 5y² + 8) and (-y² + 11).

7x² + 5y² + 8 -y² + 11 =

7x² + (5y² - y²) + (8 + 11) =

7x² + 4y² + 19 → sum

Then, we must subtract the sum to 4x² - 3y² - 7.

( 7x² + 4y²  + 19) - (4x² - 3y² - 7) =

(7x² - 4x²) + (4y² + 3y²) + (19 + 7) =

Final Answer: 3x² + 7y² + 26

28.) -x + 2y + -2z

(-2x + y - 3z)+ ( x - y - z) =

(-2x + x) + (y + y) + (-3z + z) =

Final Answer: -x + 2y + -2z

29 and 30.)

Finding the perimeter of the rectangle:

Using the formula P = 2 (l + w), substitute the following given.

P = 2 ( 4b + 7) + (2b + 3)

P = 2 ( 6b + 10)

P = 12b + 20 m

Finding the perimeter of the square:

Using the formula P = 4 s, substitute the following given.

P = 4 (3b + 2)

P = 12b + 8 m

Therefore, perimeter of the rectangle is longer than the perimeter of the square.

12b + 20 - 12b + 8 = 12

The perimeter of the rectangle is 12m longer than the perimeter of the square.