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The sum of three numbers is 117. The second is 4 more than the first and the the third is 4 more than the second. What are the numbers?

Sagot :

35+ 39+ 43
equals to 117
First number: x
Second number: x + 4 (four more than the first number)
Third number: (x+4) + 4   or   x+8  (four more than the second number)

Sum of the numbers = 117
(x) + (x+4) + (x+8) = 117
3x + 12 = 117
3x + 12 - 12 = 117 - 12
3x = 105
3x/3 = 105/3
x = 35

The numbers are:
 First: x = 35
Second number:  x + 4 = 35 + 4 = 39
Third number: (x + 4) + 4 = 35 + 8 = 43

To check:
35 + 39 + 43 = 117