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the map below shows the location of the different municipality in the province of bukidnon each unit on the coordinate plane is equivalent to 10 km determine the shortest distance between the given pairs of municipalities by using the distance formula

sincire answer please ​

The Map Below Shows The Location Of The Different Municipality In The Province Of Bukidnon Each Unit On The Coordinate Plane Is Equivalent To 10 Km Determine Th class=

Sagot :

Haberbubuidn

Answer:

1. 10√49 or 70km

2. 10√17 or 41.23km

3. 10√6 or 24.49km

4. 50km

5. 30km

Step-by-step explanation:

grade 10 student here

1.(-5,5) and (2, 5)

d =√(x2 - x1)^2 + (y2 - y1)^2

d =√(2 - (-5))^2 + (5 - 5)^2

d =√(7)^2 + (0)^2

d =√49 = 7

d = (7)(10) = 70km/(√49)(10) = 10√49

2.(2,-1) and (-2,-2)

d =√(x2 - x1)^2 + (y2 - y1)^2

d =√(-2 - 2)^2 + (-2 - (-1))^2

d =√(-4)^2 + (-1)^2

d =√16 + 1

d = √17 = 4.12

d = (4.12)(10) = 41.23km/(√17)(10) = 10√17

3.(2,-1) and (2,5)

d =√(x2 - x1)^2 + (y2 - y1)^2

d =√(2 - 2)^2 + (5 - (-1))^2

d =√(0)^2 + (6)^2

d =√6 = 2.45

d = (2.45)(10) = 24.49km/(√6)(10) = 10√6

4.(-2,-2) and (1,2)

d =√(x2 - x1)^2 + (y2 - y1)^2

d =√(1 - (-2))^2 + (2 - (-2))^2

d =√(3)^2 + (4)^2

d =√9 + 16

d =√25 = 5

d = (5)(10) = 50km

5.(-2,-2) and (-2,1)

d =√(x2 - x1)^2 + (y2 - y1)^2

d =√(-2 - (-2))^2 + (1 - (-2))^2

d =√(0)^2 + (1 - (3)^2

d =√9 = 3

d = (3)(10) = 30km

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